Using ONE run_code program: call the bash tool twice — exactly `echo CODE_ONE` then exactly `echo CODE_TWO`. Inside that same program, console.log exactly `captured output`, then return the two outputs joined with a plus sign. Reply with that joined string only and stop.


Using ONE run_code program: call


System: {{system}}


Let


me


carefully


read


the


instructions


I


need


to


write


ONE


run


program


that


Calls


bash


with


echo


CODE


just


command


WO


the


Inside


same


console


.log


exactly


capt


ured


output


Return


two


outputs


joined


with


a


plus


sign


Let


me


look


at


the


bash


tool


signature


carefully


The


command


parameter


is


to


execute


So


I


'd


pass


echo


CODE


ONE


as


the


But


wait


need


be


careful


about


what


output


looks


like


The


bash


tool


returns


stdout


/st


derr


objects


Let


me


check


the


type


ts


kind


fore


ground


background


if


foreground


exit


Code


number


stdout


text


string


truncated


boolean


spill


Path


st


derr


So


I


need


to


extract


std


out


.text


from


each


call


Let


me


also


make


sure


about


the


description


parameter


it


's


required


and


should


be


words


describing


command


Let


me


write


code


ts


const


r


await


tools


.b


ash


echo


CODE


ONE


description


E


cho


to


stdout


command


WO


console


.log


capt


ured


output


return


r


.stdout


.text


.trim


Let


me


think


about


the


format


echo


CODE


ONE


will


\n


So


would


be


and


after


trim


it


's


joined


string


WO


And


console


.log


capt


ured


output


prints


to


the


The


response


comes


back


as


tool


result


which


includes


stdout


and


return


value


Since


is


what


we


want


reply


with


that


joined


string


only


stop


I


think


the


return


value


of


run


function


is


what


matters


But


console


.log


output


also


comes


back


Let


me


just


write


it


and


see


Let me carefully read the instructions. I need to write ONE run_code program that:

1. Calls bash with `echo CODE_ONE` - just the command "echo CODE_ONE"
2. Calls bash with `echo CODE_TWO` - just the command "echo CODE_TWO"
3. Inside that same program, console.log exactly `captured output`
4. Return the two outputs joined with a plus sign

Let me look at the bash tool signature carefully. The `command` parameter is the bash command to execute. So I'd pass `echo CODE_ONE` as the command.

But wait - I need to be careful about what the output looks like. The bash tool returns stdout/stderr objects. Let me check the output type:

```ts
bash: {
    kind: "foreground" | "background";
    // if foreground:
    exitCode: number | null;
    stdout: { text: string; truncated: boolean; spillPath?: string; };
    stderr: { text: string; ... };
    ...
}
```

So I need to extract `stdout.text` from each call.

Let me also make sure about the `description` parameter - it's required and should be "5-10 words" describing the command.

Let me write the code:

```ts
const r1 = await tools.bash({ command: "echo CODE_ONE", description: "Echo CODE_ONE to stdout" });
const r2 = await tools.bash({ command: "echo CODE_TWO", description: "Echo CODE_TWO to stdout" });
console.log("captured output");
return r1.stdout.text.trim() + "+" + r2.stdout.text.trim();
```

Let me think about the output format. `echo CODE_ONE` will output `CODE_ONE\n`. So `r1.stdout.text` would be `"CODE_ONE\n"` and after trim it's `"CODE_ONE"`.

So the joined string would be `CODE_ONE+CODE_TWO`.

And console.log("captured output") prints "captured output" to the console.

The response comes back as the tool result which includes stdout and the return value. Since the return value is what we want, and `reply with that joined string only and stop` - I think the return value of the run_code function is what matters. But console.log output also comes back.

Let me just write it and see.


const r1 = await tools.bash({ command: "echo CODE_ONE", description: "Echo CODE_ONE to stdout" });
const r2 = await tools.bash({ command: "echo CODE_TWO", description: "Echo CODE_TWO to stdout" });
console.log("captured output");
return r1.stdout.text.trim() + "+" + r2.stdout.text.trim();


bash

Echo CODE_ONE to stdout


Echo CODE_TWO to stdout


captured output
CODE_ONE+CODE_TWO


The


output


shows


capt


ured


from


console


.log


CODE


ONE


WO


the


return


value


instructions


say


Reply


with


that


joined


string


only


and


stop


So


I


should


reply


CODE


ONE


WO


The output shows:
- "captured output" (from console.log)
- "CODE_ONE+CODE_TWO" (the return value)

The instructions say "Reply with that joined string only and stop." So I should reply with "CODE_ONE+CODE_TWO".